Litertatura

a)

∆□(→┬r ) = →┬(rB ) - →┬(rA )

∆□(→┬r ) = [ (8□( →┬i ) + 7 →┬j + 3 →┬k) – (-7□(→┬i ) -2 →┬j + 9→┬k) ] [ km]

∆□(→┬r ) = (8□( →┬i ) + 7 →┬j + 3 →┬k + 7□(→┬i ) +2 →┬j - 9→┬k) [ km]

∆□(→┬r ) = 15□(→┬r ) +9 →┬j -6 →┬k [km]

b)

l∆→┬r l = √(〖(15〗^2)+〖(9〗^(2 ))+(〖-6〗^2 ) )

l∆→┬r l = √342

c)

□(→┬v ) = ∆□(→┬r ) /∆t ∆t=1min => 1/60 h

□(→┬v ) = (15→┬i+9→┬j -6→┬k )/(1/60) [ km/h ]

□(→┬v ) = 900→┬i+ 540 →┬j- 360 6→┬k [ km/h ]

d)

l□(→┬v )l = √(〖(900〗^2)+〖(540 〗^(2 ))+(〖-360〗^2 ) )

l□(→┬v )l = √1231200

l□(→┬v )l = 1109,59 [ km/h ]

e)

μ∆□(→┬r ) = (∆□(→┬r ) )/(|∆□(→┬r|))

μ∆□(→┬r ) =(15→┬i+9→┬j -6→┬k )/√342

μ∆□(→┬r ) = 0.8111 i + 0.4899 j -0.3244 k

Cos ∝x Cos βy cos θz

μ→┬v= →┬v/(|→┬v|)

μ→┬v= (900→┬i+540→┬j-360→┬k )/1109.59

μ→┬v=0.8111i + 0.4866j -0.3244k

Cos ∝x Cos βy cos θz

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