Método de igualación
ivanna jadanApuntes19 de Octubre de 2022
377 Palabras (2 Páginas)70 Visitas
►Igualación:
[pic 1]
x= 3- 4y
x= (-5+2y)/3
• 3-4y = (-5+2y)/3
3(3-4y) = -5 +2y
9 - 12y = -5+2y
-12y-2y = -5-9[pic 2]
-14y = -14
y= -14/-14
y= 1
•x+4(1) = 3
x+4 = 3
x = 3-4
x = -1
[pic 3]
x = (13+4y)/3
x = (3-3y)/2
• (13+4y)/3 = (3-3y)/2[pic 4]
2(13+4y) = 3(3-3y)
26+8y = 9-9y
8y+9y = 9-26
17y = -17
y = -17/17
y = -1
•3x-4(-1) = 13
3x+4 = 13
3x = 13-4
3x = 9
x = 9/3
x = 3
[pic 5]
u = 5-v
u = 7+v
• 5-v = 7+v
-v-v = 7-5
-2v = 2
v = 2/-2[pic 6]
v = -1
• u+(-1) = 5
u-1 = 5
u = 5+1
u = 6
[pic 7]
x = -7+2y
x = (-9-3y)/5
• -7+2y = (-9-3y)/5
5(-7+2y) = -9-3y
-35+10y = -9-3y
10y+3y = -9+35
13y = 26
y = 26/13
y = 2
• x-2(2) = -7
x-4 = -7+4
x = -3
[pic 8]
• 4x-3y-3x+7y = 2 → x+4y = 2
• x+5y-y = 4+2 → x+4y = 6
x = 2-4y
x = 6-4y
• 2-4y = 6-4y
-4y+4y = 6-2
0 = 4 → No existe solución
[pic 9]
p = (7-11q)/5
p = (33-22q)/10
• (7-11q)/5 = (33-22q)/10
10(7-11q) = 5(33-22q) →dividir para 5
2(7-11q) = 33-22q
14-22q = 33-22q
-22q+22q = 33-14
0 = 19 →No hay solución
[pic 10]
4→y = 3-6z-2x
5→(-1) y = -1+4z+x
6→y = (2+2z-3x)/2
•Igualar e. 4 y 5
3-6z-2x = -1+4z+x
-6z-2x-4z-x = -1-3
-10z-3x = -4
-3x = -4+10z
7→x = (-4+10z)/-3
•Igualar e. 5 y 6
-1+4z+x = (2+2z-3x)/2
2(-1+4z+x) = 2+2z-3x
-2+8z+2x = 2+2z-3x
8z+2x-2z+3x = 2+2
6z+5x = 4
5x = 4-6z
8→x = (4-6z)/5
•Igualar e. 7 y 8
(-4+10z)/-3 = (4-6z)/5
5(-4+10z) = -3(4-6z)
-20+50z = -12+18z
50z-18z = -12+20
32z = 8
z = 8/32
z = 1/4 → 0,25
•Reemplazar e. 8
x = (4-6(0,25)/5
x = (4-1,5)/5
x = 2,5/5
x = 1/2 → 0,5
•Reemplazar e. 4
y = 3-6(0,25)-2(0,5)
y = 3-1.5-1
y = 1/2 → 0,5
[pic 11]
4→ x = 10-4y-3z
5→ x = (-2-2y+2z)/4
6→ x = (11+y-z)/3
•Igualar e. 4 y 5
10-4y-3z = (-2-2y+2z)/4
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