Limite De X
Enviado por ninja1300 • 14 de Octubre de 2013 • 400 Palabras (2 Páginas) • 235 Visitas
-lim┬(x -3)〖(x^2+x-6)/(x^2-9)〗
When we have such a limit, we use the factorization
Up we find a value that is multiplied "Y" and added "x". The values --2 and +3. So would:
((x+3)(x-2))/((x-3)(x+3))=
Down we use the square root of both terms. Change the sign to negative and the other remains positive
((x+3)(x-2))/((x-3)(x+3))=
Divide and replace -3 in X
(-3-2 )/(-3-3)=(-5)/(-6)
=5/6
lim┬(x -3)〖(x^2+x-6)/(x^2-9)〗
When we have such a limit, we use the factorization
Up we find a value that is multiplied "Y" and added "x". The values --2 and +3. So would:
((x+3)(x-2))/((x-3)(x+3))=
Down we use the square root of both terms. Change the sign to negative and the other remains positive
((x+3)(x-2))/((x-3)(x+3))=
Divide and replace -3 in X
(-3-2 )/(-3-3)=(-5)/(-6)
=5/6
lim┬(x -3)〖(x^2+x-6)/(x^2-9)〗
When we have such a limit, we use the factorization
Up we find a value that is multiplied "Y" and added "x". The values --2 and +3. So would:
((x+3)(x-2))/((x-3)(x+3))=
Down we use the square root of both terms. Change the sign to negative and the other remains positive
((x+3)(x-2))/((x-3)(x+3))=
Divide and replace -3 in X
(-3-2 )/(-3-3)=(-5)/(-6)
=5/6
lim┬(x -3)〖(x^2+x-6)/(x^2-9)〗
When we have such a limit, we use the factorization
Up we find a value that is multiplied "Y" and added "x". The values --2 and +3. So would:
((x+3)(x-2))/((x-3)(x+3))=
Down we use the square root of both terms. Change the sign to negative and the other remains positive
((x+3)(x-2))/((x-3)(x+3))=
Divide and replace -3 in X
(-3-2
...