Matemáticas 1 Actividad de adquisición del conocimiento
jorgeroelTrabajo16 de Noviembre de 2015
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UNIVERSIDAD AUTÓNOMA DE NUEVO LEÓN
PREPARATORIA No.19
MATEMÁTICAS 1
ACTIVIDAD DE ADQUISICIÓN DEL CONOCIMIENTO
Maestro: Julio Adrián Alonso Flores
Grupo: 01
Integrantes: Matricula
Carlos Enrique Flores Salvador 1812957
Paulina Anel Martínez Herrera 1814643
Daniel Alejandro Mata Alvarado 1801466
Juan Ángel Mendoza Calderón 1801652
Ismael Antonio Quiroz Galván 1804398
Clariza Yaressi Ríos Hernández 1812327
García, N.L a 15 De Noviembre del 2015
EXPRESSION | VALUES | SUBSTITUTION | RESULT |
3x-5y+8 | X=4 | 3(4) – 5(7) + 8 | -15 |
X2+7y-12 | X=-3 | + 7(5) – 12[pic 3] | 32 |
-x+4y2+5 | X=2 | -2 + 4 + 5[pic 4] | 7 |
X2+y2-13 | X=-2 | + – 13[pic 5][pic 6] | 0 |
2x2-5y2+8 | X=-2 | 2 - 5 + 8[pic 7][pic 8] | -4 |
1-Evaluate the following expressions in two variables with the values given in the second column, then discuss in plenary the result and mistakes.
2. Graph Method
A) For each of the following linear equations, find the value of “Y” to obtain the expression in terms of “X”
B) Select three values of “X” and evaluate them in this last expression.
C) Draw the graph or each equation joining the 3 corresponding points in them coordinate systems given in the following table.
D) Identify the point of intersection of the two graphs.
LINEAR EQUATIONS | LINEAR EQUATION OF Y IN TERMS OF “X” | GIVEN VALUES OF “X” | CORRESPONDING VALUES OF “Y” (EVALUATION) | COORDINATED POINT (X,Y) |
X + y= 3 |
| -1 0 1 | 4 3 2 | A=(-1,4) B=( 0,3) C= (1,2) |
3x – y= 5 |
| 2 1 0 | -1 -2 -3 | A= (2,1) B= ( 1, -2) C=( 0, -5) |
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