Formulary Physics
RoviedoApuntes13 de Febrero de 2018
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Physics I Formulary[pic 1][pic 2][pic 3][pic 4][pic 5][pic 6][pic 7][pic 8][pic 9][pic 10]
Vectors | |||
Fx = F ⋅ Cosθ | Fy = F ⋅ Sinθ | θ = Tan−1 Fy Fx | |
FR = | (∑Fx)2 + (∑Fy)2 |
ONE DIMENSIONAL MOTION | |||
U.L.M. | A.U.L.M | ||
Constant Velocity No acceleration a=0 | over “x” axis a = ΔV Δt | Free Fall | Upward Vertical Throw |
g ↓ (−) y(−) V ↓ (−) | g ↓ (−) y(+) V ↑ (+) V ↓ (−) | ||
(“x” = “y”) a = ag = g g = 9.8 m/s2 g = 980 cm/s2 G = 32 ft/s2 | |||
a = V − Vo t | V f = Vo + gt | ||
V = Δx Δt | V f = Vo + at | gt 2 y = yo + Vo t + 2 | |
V = x t | 2 x = x + V t + at o o 2 | V 2 = V 2 + 2gΔy f o | |
Δx = x f − xo | V 2 = V 2 + 2aΔx f o | (V + V ) y = y + o f t o 2 | |
Δt = t f − to | (V + V ) x = x + o f t 0 2 | Remember that when the velocity is decreasing, then the acceleration is negative. If is increasing then the acceleration is positive If starts from the rest the initial velocity is zero and if it brakes until stop at the end then the final velocity is zero. |
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