EJERCICIO DE COSTOS
Enviado por Natalia Jisseth Méndez • 20 de Mayo de 2020 • Trabajos • 548 Palabras (3 Páginas) • 78 Visitas
EJERCICIO No. 2
FORMULAS:
- Marítima = 0.50 mts x 0.50 mts x 0.50 mts x 2100 bultos = 262.5 m3
- Terrestre = 0.50 mts x 0.50 mts x 0.50 mts x 2100 bultos = 103.7 m3
2.53
[pic 3]
Volumen: 262.5 m3 x US 75 = US 19,687.5
Peso: 46.29 ton x US 75 = US 3,471.8
[pic 4]
FLETE A CANCELAR
Formula | Total | |
Tarifa básica | 262.5 m3 x US 75 | =US 19,687.5 |
BAF | US 23 x 262.5 m3 | = US 6,037.5 |
CAF | (12.5%) (19,687.5) | = US 2,460.9 |
THC | US 8 x 262.5 m3 | = US 2100 |
Alquiler del contenedor | US 98 x 17 días | =US 1,666 |
TOTAL | - | = US 31,951.9 |
= COP 127,301,491.90 |
TERRESTRE
- Volumen: 103.7 m3 x US 21 = US 2,177.7
- Peso: 42 ton x US 21 = US 882
SUMATORIA DE FLETES
- Flete Marítimo: US 31,951.9
- Flete Terrestre: US 882[pic 5]
US 32.833.9
2100 - Bultos
US 15.63 -Un bulto [pic 6]
20 - kilos[pic 7]
US 0.78 - Un kilo
2 - Libras [pic 8]
US 0.39 - Una libra
US a COP
TRM 39,84.16 | DÓLARES | formula | PESOS |
Total del flete | US 32,833.9 | X =32,833.9 x 39,84.16 = 1 | COP 130,815.511,02 |
1 Bulto | US 15.63 | X = 15.63 x 39,84.16= 1 | COP 62,272,42 |
1 Kilo | US 0.78 | X= 0.78 x 39,84.16 = 1 | COP 3,107,64 |
1 libra | US 0.39 | X= 0.39x 39,84.16 = 1 | COP 1,553,82 |
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