ECUACIONES
Enviado por pato0981 • 5 de Junio de 2014 • 332 Palabras (2 Páginas) • 179 Visitas
Apartir de la ecuacion proporcionaada obten los elementos que componen a diche elipse.
1) 1x2/81 + y2/36= 1
1x2/81 + y2/36 = 1
x/9 + y/6= 1
y/6= 1 -x/9
y= 6 (1 -x/9)
y= 6 (1 -(2)/9)
Y= 6 (1 + 2/9)
Y= 6 (1 + .22)
Y= 7.3
1x2/81 + y2/36 = 1
x/9 + y/6= 1
y/6= 1 -x/9
y= 6 (1 -x/9)
y= 6 (1 - (-1)/9)
y= 6 (1 + 1/9)
y= 6 (1 + .11)
y= 6.6
1x2/81 + y2/36 = 1
x/9 + y/6= 1
y/6= 1 -x/9
y= 6 (1 -x/9)
y= 6 (1 + 0/9)
y= 6 (1 + 0)
y= 6
1x2/81 + y2/36 = 1
x/9 + y/6= 1
y/6= 1 -x/9
y= 6 (1 -x/9)
y= 6 (1 – 1/9)
y= 6 (1 + .11)
y= 6.6
1x2/81 + y2/36 = 1
x/9 + y/6= 1
y/6= 1 -x/9
y= 6 (1 -x/9)
y= 6 (1 + 2/9)
y= 6 ( 1 + .22)
y= 7.3
2.- X2/64 + Y2/100 = 1
x/8 + y/10 =1
y/10 = 1 x/8
y= 10(1 -x/8)
y=10(1 - (-2)/8)
y=10(1 + 2/8)
y=10(1 + .25)
y= 12.5
X2/64 + Y2/100 = 1
x/8 + y/10 =1
y/10 = 1 x/8
y= 10(1 -x/8)
y=10(1 – (-1/8)
y=10(1 + 1/8)
y=10(1 + .12)
y= 11.2
X2/64 + Y2/100 = 1
x/8 + y/10 =1
y/10 = 1 x/8
y= 10 (1 – x/8)
y= 10 (1 – 0/8)
y= 10 (1 + 0)
y= 10
X2/64 + Y2/100 = 1
x/8 + y/10 =1
y/10 = 1 x/8
y= 10 1x /8
y= 10 (1 - x/8)
y= 10 (1 - 1/8)
y= 10 (1 + .12)
y= 11.2
X2/64 + Y2/100 = 1
x/8 + y/10 =1
y/10 = 1 x/8
y= 10 1x /8
y= 10 (1 - x/8)
y= 10 (1 - 2/8)
y=10 (1 + .25)
y= 12.5
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