PERIMETRO
Enviado por Vrto • 15 de Febrero de 2014 • Tareas • 407 Palabras (2 Páginas) • 182 Visitas
PERIMETRO
Enrocamiento 1
AB =√(〖(0-3)〗^2+〖(0-0)〗^2 ) = √(〖(-3)〗^2+〖(0)〗^2 ) = √9 = 3
BC = √(〖(3-5)〗^2+( 0-4)^2 ) = √(〖(-2)〗^2+〖(-4)〗^2 ) = √(4+16) = 20=4.47
CA = √(〖(5-0)〗^2+〖(4-0)〗^2 ) = √(〖(5)〗^2+〖(4)〗^2 ) = √(25+16) = 41=6.40
PERIMETRO = 13.87 m
Corazón
AB = √(〖(4-3) 〗^2+〖(0-0)〗^2 ) = √(〖(1)〗^2+〖(0)〗^2 ) = √1 = 1
BC = √(〖(5-4)〗^2+〖((-1)-0)〗^2 ) = √((1+〖(-1)〗^2 ) = √2 = 1.41
CD = √(〖(7-5)〗^2+〖((-1)-(-1))〗^2 ) =√(〖(2)〗^2+〖(0)〗^2 ) =√4 = 2
DE = √(〖(8-7)〗^2+〖(0-(-1)〗^2 ) =√(〖(1)〗^2+〖(1)〗^2 ) = √2 = 1.41
EF = √(〖(9-8)〗^2+〖(0-0)〗^2 ) =√((1)^2+〖(0)〗^2 ) =√1 = 1
FG = √(〖(7-9)〗^2+〖(4-0)〗^2 ) = √(〖(-2)〗^2+〖(4)〗^2 ) = √20 = 4.47
GH = √(〖(5-7)〗^2+〖(4-4)〗^2 ) = √(〖(-2)〗^2+〖(0)〗^2 ) =√2 = 2
HA =√(〖(0-5)〗^2+〖(0-4)〗^2 ) = √(〖(-5)〗^2+〖(-4)〗^2 ) = √41= 6.40
PERIMETRO = 16.69 m
Filtro
AB = √(〖(10-9)〗^2+〖(0-0)〗^2 ) =√(〖(1)〗^2+〖(0)〗^2 ) = √1 = 1
BC = √(〖(8-10)〗^2+〖(4-0)〗^2 ) = √(〖(-2)〗^2+〖(4)〗^2 ) = √20 = 4.47
CD = √(〖(7-8)〗^2+〖(4-4)〗^2 ) =√(〖(1)〗^2+〖(0)〗^2 ) =√1 = 1
DA = √(〖(9-7)〗^2+〖(0-4)〗^2 ) =√(〖(2)〗^2+〖(-4)〗^2 ) = √20 = 4.47
PERIMETRO = 10.94 m
Enrocamiento 2
AB= √(〖(13-10)〗^2+〖(0-0)〗^2 ) = √(〖(3)〗^2+〖(0)〗^2 ) = √9 = 1.73
BC = √(〖(8-13)〗^2+〖(4-0)〗^2 ) =√(〖(-5)〗^2+〖(4)〗^2 ) √41 = 6.40
CA = √(〖(10-8)〗^2+〖(0-4)〗^2 ) √(〖(2)〗^2+〖(-4)〗^2 ) = √20 = 4.47
PERIMETRO: 12.6 m
Área
Enrocamieno 1
0 0
3 0
5 4
0 0
...