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Vendedor viajero

Carlitos ReyesEnsayo17 de Junio de 2016

411 Palabras (2 Páginas)159 Visitas

Página 1 de 2

Problema del vendedor Viajero para 7 ciudades

Carlos Reyes Valderrama.

En primera instancia tenemos:

 

1

2

3

4

5

6

7

1

0

x12

x13

x14

x15

x16

x17

2

x21

0

x23

x24

x25

x26

x27

3

x31

x32

0

x34

x35

x36

x37

4

x41

x42

x43

0

x45

x46

x47

5

x51

x52

x53

x54

0

x56

x57

6

x61

x62

x63

x64

x65

0

x67

7

x71

x72

x73

x74

x75

x76

0

[pic 1]

[pic 2]

[pic 3]

[pic 4]

[pic 5]

[pic 6]

[pic 7]

x12 + x13 + x14 + x15 + x16 + x17 = 1

 x21 + x23 + x24 + x25 + x26 + x27 = 1

x31 + x32 + x34 + x35 + x36 + 317 = 1

x41 + x42 + x43 + x45 + x46 + x47 = 1

x51 + x52 + x53 + x54 + x56 + x57 = 1

x61 + x62 + x63 + x64 + x65 + x67 = 1

x71 + x72 + x73 + x74 + x75 + x76 = 1

x21 + x31 + x41 + x51 + x61 + x71 = 1

x12 + x32 + x42 + x52 + x62 + x72 = 1

x13 + x23 + x43 + x53 + x63 + x73 = 1

x14 + x24 + x34+ x54 + x64 + x74 = 1

x15 + x25 + x35 + x45 + x65 + x75 = 1

x16 + x26 + x36 + x46 + x56 + x76 = 1

x17 + x27 + x37 + x47 + x57 + x67 = 1

u2 - u3 + 7 x23 <= 6

u2 - u4 + 7 x24 <= 6

u2 - u5 + 7 x25 <= 6

u2 – u6 + 7x26 <= 6

u2 – u7 + 7x27 <= 6

u3 - u2 + 7 x32 <= 6

u3 - u4 + 7 x34 <= 6

u3 - u5 + 7 x35 <= 6

u3 – u6 + 7 x36 <= 6

u3 – u7 + 7 x37 <= 6

u4 - u2 + 7 x42 <= 6

...

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