Factorizacion
Vlad TepesApuntes27 de Febrero de 2022
395 Palabras (2 Páginas)137 Visitas
- F(x) = -x Conjunto D: (-5,-3,-1,0,1,3,5)
x | Y = - x |
-5 | Y= -(-5)=5 |
-3 | Y= -(-3)=3 |
-1 | Y=-(-1)=1 |
0 | Y=-(0)=0 |
1 | Y=-(1)=-1 |
3 | Y=-(3)=-3 |
5 | Y=-(5)=-5 |
[pic 1]
- F(x) = 2x + x Conjunto D: (-3,-2-1,0,1,2,3)
x | Y=2x + x |
-3 | Y= 2(-3) + (-3) = -6 – 3 = -9 |
-2 | Y= 2(-2) + (-2) = -4 – 2 = -6 |
-1 | Y= 2(-1) + (-1) = -2 -1 = -3 |
0 | Y= 2(0) + (0) = 0 |
1 | Y = 2(1) + (1)= 3 |
2 | Y= 2(2)+2=6 |
3 | Y=2(3)+3=9 |
[pic 2]
- F(x) = x2/2 Conjunto D: (-3,-2-1,0,1,2,3)
x | Y= x2/2 |
-3 | Y= (-3)2/2= 9/2 |
-2 | Y= (-2)2/2= 4/2 = 2 |
-1 | Y= (-1)2/2= 1/2 |
0 | Y= (0)2/2 = 0 |
1 | Y = (1)2/2 = ½ |
2 | Y= (2)2/2= 4/2 = 2 |
3 | Y=(3)2/2 = 9/2 |
[pic 3]
- F(x)= -x2+ 3x Conjunto D: (-1,0,1,1.5,2,3,4)
X | Y = -x2+ 3x |
-1 | Y= -(-1)2 + 3(-1) = -1-3 = -4 |
0 | Y= -(0)2 + 3(0)= 0 |
1 | Y=- (1)2 + 3(1)= -1 + 3 = 2 |
1.5 | Y=- (1.5)2 + 3(1.5)=- (9/4) + (9/2) = 9/4 = 2.25 |
2 | Y= -(2)2 + 3(2)= -4 + 6 = 2 |
3 | Y= -(3)2 + 3(3)= -9 + 9 = 0 |
4 | Y= -(4)2 + 3(4)= -16 + 12 = -4 |
[pic 4]
- F(x) = 50/x2-25 Conjunto D: (-3,-2,-1,0,1,2,3,4,6,7,8)
X | Y=50/x2-25 |
-3 | Y= 50/(-3)2 – 25 = 50/9 – 25 = 50/-16 = -3.125 |
-2 | Y= 50/(-2)2 – 25 = 50/4 – 25 = 50/-21 = -2.3809 |
-1 | Y= 50/(-1)2 – 25 = 50/1-25 = 50/-24 = -2.08333 |
0 | Y= 50/(0)2 – 25 = 50/0-25 = 50/-25=-2 |
1 | Y= 50/(1)2 – 25 = 50/1-25 = 50/-24 = -2.08333 |
2 | Y= 50/(2)2 – 25 = 50/4 – 25 = 50/-21 = -2.3809 |
3 | Y= 50/(3)2 – 25 = 50/9 – 25 = 50/-16 = -3.125 |
4 | Y= 50/(4)2 – 25 = 50/16 – 25 = 50/-9 = -5.555 |
6 | Y= 50/(6)2 – 25 = 50/36 – 25 = 50/11 = 4.5454 |
7 | Y= 50/(7)2 – 25 = = 50/49 – 25 = 50/24 = 2.08333 |
8 | Y= 50/(8)2 – 25 = 50/64 – 25 = 50/39=1.282 |
[pic 5]
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