Taller microecnomia
KmlogjoseTrabajo2 de Febrero de 2022
5.914 Palabras (24 Páginas)103 Visitas
- Plantear las respectivas funciones de demanda de la forma Q = F (P) y elaborar sus respectivas tablas y graficar sus curvas de demanda.
Forma algebraica
- Q + 2P – 20 = 0
Q= 20 – 2P
Tabla de demanda
P | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
Q | 20 | 18 | 16 | 14 | 12 | 10 | 8 | 6 | 4 |
Q=20-2P Q=20-2P Q=20-2P Q=20-2P Q=20-2P Q=20-2P
20-2(0) =20-2(1) =20-2(2) =20-2(3) =20-2(4) =20-2(5)
=20 =18 = 16 =14 =12 =10
Q=20-2P Q=20-2P Q=20-2P
=20-2(6) =20-2(7) =20-2(8)
=8 =6 =4
[pic 1]
- 80-2Q=10P
Forma algebraica
Q= 80/2 - 10P/2
Q= 40 – 5P
Tabla de demanda
P | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
Q | 40 | 35 | 30 | 25 | 20 | 15 | 10 | 5 | 0 |
Q= 40 – 5P Q= 40 – 5P Q= 40 – 5P Q= 40 – 5P Q= 40 – 5P Q= 40 – 5P
=40-5(0) =40-5(1) =40-5(2) =40-5(3) =40-5(4) =40-5(5)
=40 =35 =30 =25 =20 =15
Q= 40 – 5P Q= 40 – 5P Q= 40 – 5P
= 40-5(6) =40-5(7) = 40-5(8)
=10 =5 =0
[pic 2]
Forma algebraica
- 2P. Q = 60
Q= 60/ 2P
Q= 30/P
Tabla de demanda
P | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | |||
Q | 30 | 15 | 10 | 7.5 | 6 | 5 | 4.2 | 3.75 | 3.33 |
Q=30/1 Q =30/2 Q =30/3 Q=30/4 Q=30/5 Q =30/6 Q=30/7 Q=30/8 Q=30/9
Q=30 Q= 15 Q=10 Q=7.5 Q=6 Q=5 Q=4.2 Q=3.75 Q=3.33
Grafica
[pic 3]
- 4Q + 12P -520 = 0
4Q= 520-12P
Q= (520-12P) /4
Q= 130-3P
Tabla de demanda
P | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
Q | 130 | 127 | 124 | 121 | 118 | 115 | 112 | 109 | 106 |
Q= 130-3P Q= 130-3P Q= 130-3P Q= 130-3P Q= 130-3P Q= 130-3P
= 130-3(1) =130-3(2) =130-3(3) =130-3(4) =130-3(5) =130-3(6)
= 127 = 124 = 121 =118 =115 =112
Q= 130-3P Q= 130-3P
= 130-3(7) =130-3(8)
=109 =106
[pic 4]
- 2Q +3P -25 = 0
Q= 12.5 – 1.5P
Tabla de la demanda
P | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
Q | 12.5 | 11 | 9.5 | 8 | 6.5 | 5 | 3.5 |
[pic 5]
Q= 12.5 – 1.5(0) Q=12.5 – 1.5(1) Q=12.5 -1.5(2) Q=12.5- 1.5(3)
Q= 12.5 Q= 12.5-1.5 Q=12.5-3 Q=12.5-4.5
Q=11 Q=9.5 Q=8
Q=12.5-1.5 (4) Q=12.5-1.5(5) Q=12.5-1.5(6)
Q=12.5-6 Q=12.5-7.8 Q=12.5-9
Q=6.5 Q=5 Q=3.5
- Plantear las respectivas funciones de oferta de la forma Q = F (P)
Forma algebraica
- Q - 2P = 12
Q= 12 + 2P
Tabla de oferta
P | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
Q | 12 | 14 | 16 | 18 | 20 | 22 | 24 | 26 | 28 |
Q= 12 + 2P Q= 12 + 2P Q= 12 + 2P Q= 12 + 2P Q= 12 + 2P Q= 12 + 2P
=12+2(0) =12+2(1) =12+2(2) =12+2(3) =12+2(4) =12+2(5)
=12 =14 =16 =18 =20 =22
Q= 12 + 2P Q= 12 + 2P Q= 12 + 2P
=12+2(6) =12+2(7) =12+2(8)
= 24 =26 =28
[pic 6]
Forma algebraica
B) 3Q - 5P = 0
Q= 5P/3
Tabla de oferta
P | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
Q | 0 | 1,66 | 3,33 | 5 | 6,66 | 8,33 | 10 | 11,66 | 13,33 |
Q= 5P/3 Q= 5P/3 Q= 5P/3 Q= 5P/3 Q= 5P/3 Q= 5P/3 Q= 5P/3
=5(0) /3 =5(1) /3 =5(2) /3 =5(3) /3 =5(4) /3 =5(5) /3 =5(6) /3
=0 =1.66 =3.33 = 5 =6.66 =8.33 =10
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