CUBICASION DE TECHUMBRE

CUBICACION TECHUMBRE

Cola de pato 1

X2 = a2 + b2

X2 = (1.20)2 + (1.80)2

X = /4.68

X = 2.16  NUEVA ALTURA

Cola de pato 2

X2 = a2 + b2

X2 = (1.20)2 + (2.25)2

X = /7.29

X = 2.70 NUEVA ALTURA

AREA DE UN TRIANGULO

AREA = (B x A) / 2

COLA DE PATO 1 COLA DE PATO 2

AREA = (4.50 x 2.16) / 2 AREA = (3.80 x 2.50) / 2

= 4.86 m2 = 4.75 m2

JUNTA LIMAOLLA

AREA 3 =2.25 x 1.91) / 2

= 3.26 m2x2

= 6.52 m2

AREA DE UN TRAPESIO

AREA = B x ((H1 + H2) / 2)

JUNTA DIAGONAL CABALLETE

AREA 5 = 2.55 x ((3.80 + 1.90) /2) AREA 6 = 2.50 x ((2.25+ 4.50) /2)

= 7.27 m2 = 7.20 m2

TRAPESIOS RESTANTES

AREA 4 = 2.55 x ((6.90 + 8.70) /2) AREA 7 = 2.13 x ((2.30 + 4.50) /2)

= 19.89 M2 x2 = 7.24 m2 x2

= 39.78 m2 = 14.48 m2

Total m2 cubierta = 85.06 m2

Caballete = 34.22 m

Tapacan = 53 m

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