Topografia

TRIANGULO (101_ 1_ 102)

1_101 = 6.00m

1_102 = 6.00m <1 = 139° 16' 18.23"

101_102 = 11.25

P=((6+6+11.25))/2

P = 11.625

P – 101 = (11.625 – 6.00) = 5.625

P – 102 = (11.625 – 6.00) = 5.625

P – 101_102 = (11.625 – 11.25) = 0.375

tan (<1)/2=√(((5.625)(5.625))/(11.625(0.375)))

(<1)/2=tan^(-1)⁡〖(2.69)〗 = <1=2(69° 〖38〗^' 〖9.11〗^'')

<1 = 139° 16' 18.23"

TRIANGULO (201_ 2_ 202)

2_201 = 6.00m

2_202 = 6.00m <2 = 99° 35' 30.58"

201_202 = 9.165

P=((6+6+9.165))/2

P = 10.5825

P – 201 = (10.5825– 6.00) = 4.5825

P – 202 = (10.5825– 6.00) = 4.5825

P – 201_202 = (10.5825–9.165) = 1.4175

tan (<2)/2=√(((4.5825)(4.5825))/(10.5825(1.4175)))

(<2)/2=tan^(-1)⁡〖(1.1831)〗 = <2=2(49° 〖47〗^' 〖45.29〗^'')

<2 = 99° 35' 30.58"

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