Conductividad de diferentes electrolitos
regan913Informe25 de Septiembre de 2015
471 Palabras (2 Páginas)128 Visitas
Objetivo:
Comprobar que se cumple la ley de Kohlrausch para soluciones diluidas de electrolitosfuertes, así como también determinar la conductividad molar de los mismos.
Determinar la conductividad molar de un electrolito débil a dilución infinita
Reactivos:
NaCl
CH3COOH
CH3COONa
HCl
CuSO4*5H2O
Prepararemos disoluciones de 1M 0.1M 0.01M y 0.001M
Diagrama de Flujo:
[pic 1]
Resultados:
Concentracion (M) | G Tambiente | Conversión s/cm | T 50°C | Conversión s/cm |
1 | 45 ms/cm | 0.0451 | 52.7 ms/cm | 0.0527 |
0.1 | 8.11 ms/cm | 0.00811 | 8.51 ms/cm | 0.00851 |
0.01 | 1367 µs/cm | 0.001367 | 1465 µs/cm | 0.001465 |
0.001 | 216.3 µs/cm | 0.0002163 | 237.2 µs/cm | 0.0002372 |
0.0001 | 34.9 µs/cm | 0.0000349 | 37.1 µs/cm | 0.0000371 |
Concentracion (M) | G Tambiente (µs/cm) | Conversión | T 50°C | Conversión |
1 | 1471 | 0.001471 | 1326 | 0.001326 |
0.1 | 711 | 0.000711 | 698 | 0.000698 |
0.01 | 1714 | 0.000067 | 149.1 | 0.0001491 |
0.001 | 67.8 | 0.0000678 | 57.4 | 0.0000574 |
0.0001 | 33.8 | 0.0000338 | 32.9 | 0.0000329 |
Concentracion (M) | G Tambiente | Conversión S/cm | T 50°C | Conversión S/cm |
1 | 9999 µs/cm | 0.009999 | 9999 µs/cm | 0.009999 |
0.1 | 10.4 ms/cm | 0.0104 | 36.4 ms/cm | 0.0364 |
0.01 | 4.52 ms/cm | 0.00452 | 4.26 ms/cm | 0.00426 |
0.001 | 1079 µs/cm | 0.001079 | 1061 µs/cm | 0.001061 |
0.0001 | 84.3 µs/cm | 0.0000843 | 70.1 µs/cm | 0.0000701 |
Concentracion (M) | G Tambiente (ms/cm) | Conversión | T 50°C | Conversión |
1 | 86.0 ms/cm | 0.086 | 95.6 ms/cm | 0.0956 |
0.1 | 10.55 ms/cm | 0.01055 | 12.22 ms/cm | 0.01222 |
0.01 | 1078 µs/cm | 0.001078 | 1362 µs/cm | 0.001362 |
0.001 | 220.7 µs/cm | 0.0002207 | 249.7 µs/cm | 0.0002497 |
0.0001 | 2085 µs/cm | 0.0002085 | 1940 µs/cm | 0.00194 |
Concentracion (M) | G Tambiente | Conversiones | T 50°C | Conversiones (S/cm) |
1 | 31.7 ms/cm | 0.0317 | 38.9 ms/cm | 0.0389 |
0.1 | 4.35 ms/cm | 0.00435 | 5.25 ms/cm | 0.00525 |
0.01 | 493 µs/cm | 0.000493 | 581 µs/cm | 0.000581 |
0.001 | 61.8 µs/cm | 0.0000618 | 99.3 µs/cm | 0.0000993 |
0.0001 | 8.22 µs/cm | 0.00001822 | 17.76 µs/cm | 0.00001776 |
Calculos:
1. donde Lele=1.05cm y R=0.4cm
sustituimos para Gtamb y para Gt50°C ejemplo para NaCl[pic 2]
= =5.81x10-3
=5.23x10-3
2 .
despejamos y sustituimos para ambas temperaturas
=
[pic 3][pic 4][pic 5][pic 6][pic 7][pic 8][pic 9][pic 10][pic 11]
3.[pic 12]
Sustituimos con las diferentes K, Ktamb y K50°C
[pic 13][pic 14][pic 15]
4. .
Sustituimos con las diferentes K, Ktamb y K50°C
[pic 16][pic 17][pic 18]
Resultados de HCl a Tamb
C | G | [pic 19] | k | Λ | ΛM | |
1 | 0.009999 | 50.0050005 | 0.019998 | 0.019998 | 19.998 | |
0.1 | 0.0104 | 48.0769231 | 0.0208 | 0.208 | 208 | |
0.01 | 0.00452 | 110.619469 | 0.00904 | 0.904 | 904 | |
0.001 | 0.001079 | 463.39203 | 0.002158 | 2.158 | 2158 | |
0.0001 | 0.0000843 | 5931.1981 | 0.0001686 | 1.686 | 1686 |
[pic 20]
Resultados de HCl a T50°C
C | G | [pic 21] | k | Λ | ΛM | |
1 | 0.009999 | 50.0050005 | 0.019998 | 0.019998 | 19.998 | |
0.1 | 0.0364 | 13.7362637 | 0.0728 | 0.728 | 728 | |
0.01 | 0.00426 | 117.370892 | 0.00852 | 0.852 | 852 | |
0.001 | 0.001061 | 471.253534 | 0.002122 | 2.122 | 2122 | |
0.0001 | 0.0000701 | 7132.66762 | 0.0001402 | 1.402 | 1402 |
[pic 22]
Resultados de NaCl a Tamb
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