Estudio de mercado en base a una encuesta realizada a 300 personas y el uso de un algoritmo que maneja COCA-COLA
Enviado por aaronadio • 4 de Noviembre de 2015 • Trabajos • 265 Palabras (2 Páginas) • 358 Visitas
E U F1
[pic 1][pic 2]
u=0.0433
a=0.04
[pic 3][pic 4]
(0.0216)(0.0418) - (8x)(-2.4639)=2.874x[pic 5][pic 6]
Nuevo valor de “a”= 2.874x[pic 7]
U1= (4.8) (e)= (4.8) (2.7189)=13.05
U1= (3.5) (e)= (3.5) (2.7189)=9.51
[pic 8][pic 9]
[pic 10]
[pic 11]
85.1511-55.688=39.931
E U F2
[pic 12][pic 13]
u=0.0433
a=0.0866
[pic 14][pic 15]
(0.0216)(0.0834) - (3.7497x)(-2.0272)=9.5107x[pic 16][pic 17]
Nuevo valor de “a”= 9.5107x[pic 18]
U1= (4.8) (e)= (4.8) (2.7189)=13.05
U1= (3.5) (e)= (3.5) (2.7189)=9.51
[pic 19][pic 20]
[pic 21]
[pic 22]
87.676-45.2198=42.4562
E U F3
[pic 23][pic 24]
u=0.0433
a=0.6433
[pic 25][pic 26]
(0.0139)(0.6451) - (0.2069)(-.3733)= 0.0911
Nuevo valor de “a”= 0.0911
U1= (4.8) (e)= (4.8) (2.7189)=13.05
U1= (3.5) (e)= (3.5) (2.7189)=9.51
[pic 27][pic 28]
[pic 29]
[pic 30]
85.1376-45.2077=39.9299
E U F4
[pic 31][pic 32]
u=0.0433
a=0.1433
[pic 33][pic 34]
(0.0216)(0.1451) - (0.0102)(-1.6691)= 0.0167
Nuevo valor de “a”= 0.0167
U1= (4.8) (e)= (4.8) (2.7189)=13.05
U1= (3.5) (e)= (3.5) (2.7189)=9.51
[pic 35][pic 36]
[pic 37]
[pic 38]
85.1507-45.2195=39.9312
E U F5
[pic 39][pic 40]
[pic 41][pic 42]
u=0.0433
a=0.0866
[pic 43][pic 44]
(0.0216)(0.0834) - (3.7497x)(-2.0272)=9.5107x[pic 45][pic 46]
Nuevo valor de “a”= 9.5107x[pic 47]
U1= (4.8) (e)= (4.8) (2.7189)=13.05
U1= (3.5) (e)= (3.5) (2.7189)=9.51
[pic 48][pic 49]
[pic 50]
[pic 51]
87.676-45.2198=42.4562
B U F5
[pic 52][pic 53]
u=0.6000
a=0.0866
[pic 54][pic 55]
(0.0133)(0.0905) - (3.7497x)(-1.5546)=0.1811[pic 56]
Nuevo valor de “a”= 0.1811
U1= (4.8) (e)= (4.8) (2.7189)=13.05
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