Impedancia Del Sistema Del Bus

Impedancia del sistema del bus

z_s1= 0.006253+j 0.023665= 0.0244∠75.19° p.u.

z_s0= 0.013109+j 0.044408= 0.0463 ∠75.55° p.u.

L1

Caracteristicas

Longitud = 11.5 Km

Conductor = ACSR 477 MCM

Hilo de guarda = AGAR 3/8”ø

Voltaje de operación 115 Kv

Z secuencia a 100 Mva

z_1 = (0.133280 + j 0.376657) 11.5

z_1 =(1.53272 + j 4.3315555)/z_base

z_1 = 0.011589 + j 0.032752

z_1 = 0.0347∠70.51°p.u.

z_0= (0.310892 + j 1.848036)* 11.5

z_0 = (3.575258 + j 21.252414)/z_base

z_0 = (0.027034 + j 0.160699

z_0 = 0.163 ∠80.45°

*PC, 2.1

Alimentador a 13.8 Kv

C1- Zavaleta

Conductor ACSR, 266.8 - 26/7

3.3 Km z_1 = (0.415511+ j 0.688898) = 0.8045 ∠58.90°

z_0 = (0.724169+ j 3.244554) = 3.3244 ∠77.42°

5.2 Km z_1 = (0.653232+ j 1.083030) = 1.2648∠58.90°

z_0 = (1.138205+ j 5.100658) = 5.226110∠77.42°

*PC, 2.2

C2- Momoxpan

Conductor ACSR, 266.8 - 26/7

4.8 Km z_1 = (0.604380+ j 1.002035) = 1.702∠58.90°

z_0 = (1.053337+ j 4.719352) = 4.835∠77.42°

6.6 Km z_1 = (0.829103+ j 1.374615) = 1.2648∠58.90°

z_0 = (1.444645 + j 6.473912) = 6.633∠77.42°

*PC, 2.3

C3- Las americas

Conductor ACSR, 266.8 - 26/7

18 Km z_1 = (0.361790+ j 0.599832) = 0.700493∠58.90°

z_0 = (0.630542 + j 2.825069) = 2.845∠77.42°

20 Km z_1 = (0.401989+ j 1.083030) = 1.2648∠58.90°

z_0 = (0.700434+ j 3.138866) = 0.7783 ∠77.42°

*PC, 2.4

C4- Panamericano

Conductor ACSR, 266.8 - 26/7

16 Km z_1 = (0.32191+ j 0.533184) = 0.6227∠58.90°

z_0 = (0.560482+ j 2.511172) = 2.572960∠77.42°

18.7 Km z_1 = (0.375860+ j 0.623159) = 0.6227∠58.90°

z_0 = (0.654906 + j 2.934840) = 3.0∠77.42°

Bus A

z_A1F z_S1 +z_L1= 0.0590 ∠72.44°

z_0 = 0.292 ∠79.37°

z_TH = 2 z_A1+z_0= 0.3266 ∠72.44°

Bus B

z_B11 z_A1 +z_T11= 0.516 ∠88.02°

z_0 = 0.459444∠90°

z_TH = 2 z_B11+z_0= 1.4912∠88.63°

Bus C

z_C11 z_A1 +z_T21= 0.5626 ∠88.02°

z_0 = 0.5061111 ∠90°

z_TH = 2 z_C1+z_0= 1.6312∠88.75°

Bus D

z_D11 z_B11 +z_C1= 0.516 ∠88.02°+ 0.8045 ∠58.90°= 1.2801 ∠70.21°

〖(z〗_T1D+z_D0+〖3 Rf〗_)

z_0 = 22.0376 ∠9.68°

z_TH = 2 z_C1+z_0= 1.6312∠88.75°

Bus H

z_H11 z_D11 +z_H1= 0.4334 + j 1.20450 + 0.23778 + j 0.39413 = 1.73381 ∠67.22°

z_0 = 0 + j 0.459444 + 0.72406+ j 3.2446 + 0.4142 + j 1.85605 + 21 = 22.8258∠14.09°

z_TH = 2 z_H11+z_0= 2(1.73381∠67.22°) + 22.139074 + j 5.556843 =

= 1.342640807 + j 3.19714 = 25.0604 ∠20.44°

Bus E

z_E11 z_B11 +z_C2= 2.1674 ∠65.55°

z_0 = 22.657 ∠13.21°

z_TH = 2 z_E11+z_0= 25.528∠20.92°

Bus I

z_I11 z_E11 +z_I1= (0.89708468 + j 1.9730337 + 0.0499503 + j 0.0828036 =

= 2.26349 ∠65.27°

z_0 = 22.0574739 + j 5.17756 + 0.391609 + j 1.754835 = 23.4950 ∠17.16°

z_TH = 2 z_I11+z_0= 2(2.26349∠65.270°) + 22.44911 + j 6.93199 = 26.7309 ∠24.40°

1.893830+ j 4.111807

Bus F

z_F11 z_C11 +z_C3=1.222 ∠71.91°

z_0 = 21.867∠8.63°

z_TH = 2 z_F11+z_0= 23.07∠14.06°

Bus J

z_J11 z_F11 +z_J1= 0.379443866 + j 1.1616 + 0.040190 + j 0.0666236 =

= 1.2980 ∠71.14°

z_0 = 21.61942 + j 3.281209707 + 0.081676 + j 0.3659973 = 22.005445 ∠9.54°

z_TH = 2 z_J11+z_0= 2(1.2980 ∠71.14°) + 21.70111 + j 3.6470971 = 23.35208 ∠15.15°

0.83917478 + j 2.456624

Bus G

z_G11 z_C11 +z_C4=1.147∠72.78°

z_0 = 21.770∠7.97°

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