ESTRUCTURA DIAGRAMA DE CUERPO LIBRE

ESTRUCTURA[pic 1] DIAGRAMA DE CUERPO LIBRE [pic 2]

SUMATORIA DE FUERZAS

∑MC = 0

        (8N × 6N) + (4N × 3N) - (Rye × 1.5M) = 0

        48N/M + 12N/M – Rye ×1.5M = 0

        60N/M – Rey × 1.5M = 0

        = Rye[pic 3]

        40N = Rye

↑+ ∑Fy = 0

        -8N – 4N – Ryc + 40N = 0

        28N = Ryc

↑+ ∑Fx = 0

        Rxc = 0

NUDO A[pic 4]

β =   = 36,86°[pic 5][pic 6]

α = 90° - 36,86° = 53,14°

[pic 7]

[pic 8]

Fab = 6N (T)

[pic 9]

Fad = 10N (C)

↑+ ∑Fy = 0

        -8N + Fad × cos36,86° = 0

        [pic 10]

        Fad = 9,99 ≈ 10N (C)

∑Fx = 0[pic 11]

        Fab – Fad × sen36,86° = 0

        Fab = 5,99 ≈ 6N (T)

NUDO D

α =  = 53,13°[pic 13][pic 12]

β =  = 53,13°[pic 14]

Fab = Fdb = 10N (T)

[pic 15]

Fae = 12N (C)

↑+ ∑Fy= 0

        10 × cos53,13° + Fdb × sen53,13° = 0

        Fdb = [pic 16]

        Fdb = 10N (T)

↑+ ∑Fx = 0

        -Fde + 10 × cos53,13° + 10 × cos53,13° = 0

        12N = Fde (C)

NUDO B

[pic 17]

α =  = 53,13°[pic 18]

β =  = 53,13°[pic 19]

↑+ ∑Fy= 0

        -4 – 10 × () + Fbe () = 0[pic 20][pic 21]

        -4 -8 + Fbe × 0,8 = 0

        Fbe = [pic 22]

        Fbe = 15N (C)

↑+ ∑Fy= 0

        -Fdb × sen53,13° - 4N + Fbe × sen53,13° = 0

        Fbe = [pic 23]

        Fbe = 15N (C)

↑+ ∑Fx= 0

        -6 – 10 × () – 15N () + Fbc= 0[pic 24][pic 25]

        Fbc = 6N + 6N + 9N

        Fbc = 21 (T)

↑+ ∑Fx= 0

        -6N + Fbc – 10N × cos53,13° - 15N × cos53,13° = 0

        Fbc = 6N + 10N × cos53,13° + 15N × cos53,13°

        Fbc = 6N + 6N + 9N

        Fbc = 21N (T)

NUDO E

[pic 26]

α =  = 53,13°[pic 27]

↑+ ∑Fy = 0

        -15 × sen53,13° - Fce × sen53,13° + 40N = 0

         = Fce[pic 28]

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