Taller de electronica. Programa

Taller de electronica.

Programa.

Fundamento de electrónica

universidad.

C. Universitaria Americana

Programa.

Ing. de sistemas

Integrantes.

Neil Calvo.

Mateo Barrios

Juan Rangel

Andrés Felipe López Pacheco

Curso.

1a1

Horario.

1:00pm a 4:00pm

Docente.

Horacio Caicedo

[pic 1]

Punto 1.

R1 = 120 Ω

R23 = R2*R3/R2+R3 = 150Ω*220/150Ω+220Ω = 33000Ω2/980Ω = 89.18Ω se cancelan los ohmios.

Paralelo

 R45 =R4*R5/R4+R5= 470Ω*510Ω /470Ω+510Ω = 239.000Ω2 /980Ω = 243.18Ω se cancelan los ohmios.

Paralelo

Re= (120+89.18+243.18) Ω = 452.36Ω

I = V/R = 9/452.36 = 0.019ª

 V= I*R = 0.019A * 452.36Ω = 8.59V

Vab= I*Rab = 0.019*120 = 2.28v

Vbc = 0.019*89.18 = 1.69v

Vcd = 0.019*243.18 = 4.6v

V = (vab+vbc+vcd) v

=2.28+1.69+ 4.6 = 8.57v - 9v = 0v

Iab I V/R = 0.019A

Ibc1 = 1.69V/950Ω = 0.011

Ibc2 = 1.69v/220Ω = 0.008

Icd1 = 4.6v/470Ω = 0.009

Icd2 = 4.6v/470Ω = 0.010

Punto 2.

[pic 2]

R1 = 560 Ω

Serie

R23 = R2*R3/R3+R4 = 270Ω*330/270Ω+330Ω =89.100Ω2/600Ω = 148.5 Ω se cancelan los ohmios.

Paralelo

 R45 =R4*R5/R4+R5= 390Ω*510Ω /3900Ω+510Ω = 198.900Ω2 /900Ω = 221Ω se cancelan los ohmios.

Paralelo

Re= (560+89.148.5+221) Ω = 929.5Ω

I = V/R = 12/929.5Ω = 0.012ª

 V= I*R = 0.012A * 929.5Ω = 11.15V

Vab= I*Rab = 0.012*560 = 6.72v

Vbc = 0.012*148.5 = 1.78v

Vcd = 0.012*221 = 2.65v

V = (vab+vbc+vcd) v

=6.72+1.78+ 2.65 = 11.15v – 11.15v = 0v

I V/R =  560 Ω  = 0.012A

Ibc1 = 1.78V/270Ω = 0.006

Ibc2 = 1.78v/330Ω = 0.005

Icd1 = 2.65v/390Ω = 0.007

Icd2 = 2.65v/510Ω = 0.0051

Punto 3.

[pic 3]

R1=270

Serie

 R23 = R2*R3/R3+R4 = 680Ω*510/680Ω+510Ω =346.800Ω2/1190Ω = 291.42 Ω se cancelan los ohmios.

Paralelo

 R45 =R4*R5/R4+R5= 220Ω*150Ω /220Ω+150Ω = 35.200Ω2 /370Ω = 95.13Ω se cancelan los ohmios.

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