El cálculo de la viscosidad y la tensión superficial de los líquidos
Enviado por romolinac • 19 de Febrero de 2015 • Prácticas o problemas • 907 Palabras (4 Páginas) • 282 Visitas
CUESTIONARIO:
1.- CON LOS DATOS OBTENIDOS EN EL EXPERIMENTO, CALCULA LA VISCOSIDAD Y LA TENSION SUPERFICIAL DE LOS LIQUIDOS QUE SE EMPLEARON
Experimento #1
(VISCOSIDAD)
Acetona
T= 20°C
μ₁= (ρ₁Ρ₁)/(ρ₀Ρ₀)(μ₀)= (0.7901 g/mol)(23s)/(0.99823 g/mol)(40s) (10.089mP)=4.5mP
T=30°C
μ₁= (ρ₁Ρ₁)/(ρ₀Ρ₀)(μ₀)= (0.7787 g/mol)(20s)/(0.99567 g/mol)(33s) (8.004mP)=3.7mP
T=50°C
μ₁= (ρ₁Ρ₁)/(ρ₀Ρ₀)(μ₀)= (0.7554 g/mol)(17s)/(0.98807 g/mol)(29.6s) (5.492mP)=2.4mP
Experimento #1
(TENSION SUPERFICIAL)
Acetona
T= 20°C
γ =ρrhg/2=((0.7901 g/mL)(0.05cm)(981 cm/s^2 )(0.2cm) )/2=3.8 dinas/cm
T=30°C
γ =ρrhg/2=((0.7787 g/mL)(0.05cm)(981 cm/s^2 )(0.4cm) )/2=7.6 dinas/cm
T=50°C
γ =ρrhg/2=((0.7554 g/mL)(0.05cm)(981 cm/s^2 )(0.6cm) )/2=11.11 dinas/cm
Experimento #2
(VISCOSIDAD)
Etanol
T= 20°C
μ₁= (ρ₁Ρ₁)/(ρ₀Ρ₀)(μ₀)= (0.8 g/mol)(50s)/(0.99823 g/mol)(40s) (10.089mP)=10.1mP
T=30°C
μ₁= (ρ₁Ρ₁)/(ρ₀Ρ₀)(μ₀)= (0.79 g/mol)(30s)/(0.99567 g/mol)(33s) (8.004mP)=5.7mP
T=50°C
μ₁= (ρ₁Ρ₁)/(ρ₀Ρ₀)(μ₀)= (0.7554 g/mol)(17s)/(0.98807 g/mol)(29.6s) (5.492mP)=2.4mP
Experimento #2
(TENSION SUPERFICIAL)
Etanol
T= 20°C
γ =ρrhg/2=((0.8 g/mL)(0.05cm)(981 cm/s^2 )(0.85cm) )/2=16.67 dinas/cm
T=30°C
γ =ρrhg/2=((0.79 g/mL)(0.05cm)(981 cm/s^2 )(0.9cm) )/2=17.43 dinas/cm
T=50°C
γ =ρrhg/2=((0.77 g/mL)(0.05cm)(981 cm/s^2 )(0.95cm) )/2=17.94 dinas/cm
Experimento #1
(VISCOSIDAD)
Acetona
T= 20°C
% error=(Vt-Vexp)/Vt x100=(3.5-4.5)/3.5 x100=28%
T=30°C
% error=(Vt-Vexp)/Vt x100=(3.1-3.7)/3.1 x100=19%
T=50°C
% error=(Vt-Vexp)/Vt x100=(2.6-2.4)/2.6 x100=7.9%
Experimento #2
(VISCOSIDAD)
Etanol
T= 20°C
% error=(Vt-Vexp)/Vt x100=(12-10.1)/12 x100=15%
T=30°C
% error=(Vt-Vexp)/Vt x100=(10-5.7)/10 x100=43%
T=50°C
% error=(Vt-Vexp)/Vt x100=(7.2-2.4)/7.2 x100=66.6%
2.- DETERMINE EL PORCENTAJE DE ERROR DE LA VISCOSIDAD OBTENIDA EXPRIMENTALMENTE.
Experimento #1
(TENSION SUPERFICIAL)
Acetona
T= 20°C
% error=(Vt-Vexp)/Vt x100=(23.8-3.8)/23.8 x100=84%
T=30°C
% error=(Vt-Vexp)/Vt x100=(22.5-7.6)/22.5 x100=66%
T=50°C
% error=(Vt-Vexp)/Vt x100=(20-11.11)/20 x100=54.4%
Experimento #2
(TENSION SUPERFICIAL)
Etanol
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