Geometria Analitica

La presa.

Cálculo de Perímetros

Enrocamiento A1

ENROCAMIENTO: A (0,0), B (10,0), C (16,30)

AB = √ (0-0)2 +(10-0)2 =√ (0)2+(10)2= √100 = 10

BC = (10-16)² +(0-30)²=(6)²+(30)²= 93630.59

CA = (16-0)²+(30-0)²=(16)²+(30)²=1154=34

PERIMETRO: = 74.59 m

Corazón A2

CORAZON: A (16, -4), B (20, -4), C (24,0), D (26,0), E (19,30), F (16,30), G (10,0), H (13,0)

AB = (16-20)²+(-4)-(-4)²=(4)²+(8)²=80= 8.9

BC = (20-24)²+(-4)-0)²=(4)²+(4)²=32=5.6

CD = (24-26)²+(0-0)²=(2)²+(0)²=4= 2

DE =(26-19)²+(0-30)²=(7)²+(30)²=949 =30.80

EF =(19-16)²+(30-30)²=(3)²+(0)²=9= 3

FG =(16-10)²+(30-0)²=(6)²+(30)²=936 = 30.59

GH =(10-13)²+(0-0)²=(3)²+(0)²=9 =3

HA = (13-16)²+(-4)-0)²=(3)²+(4)²=27= 5.19

PERIMETRO = 88.89 m

Filtro A3

FILTRO: A (26,0), B (27,0), C (20,30), D (19,30)

AB =(26-27)²+(0-0)²=(1)²+(0)²=1

BC = (27-20)²+(0-30)²=(7)²+(30)²=949 = 30.80

CD = (20-19)²+(30-30)²=(1)²+(0)²=1 = 1

DA = (19-26)²+(0-30)²=(7)²+(30)²=949 = 30.80

PERIMETRO = 63.6 m

Enrocamiento A4

ENROCAMIENTO: A (27,0), B (37, 0), C (20,30)

AB= (27-37)²+(0-0)²=(10)²+(0)²=100 = 10

BC = (37-20)²+(0-30)²=(17)²+(30)²=1189 = 34.48

CA = (27-20)²+(0-30)²=(7)²+(30)²=949 = 30.80

PERIMETRO: 75.28 m

Cálculo de Áreas:

Enrocamiento A1

ENROCAMIENTO: A (0,0), B (10,0), C (16,30)

Multiplicamos en diagonal hacia abajo y luego hacia arriba en diagonal para después sumar y obtener el área de todas las secciones.

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