10 ejercicios de mecanismos
Enviado por axela133 • 24 de Abril de 2020 • Tareas • 3.411 Palabras (14 Páginas) • 232 Visitas
10 Ejercicios de mecanismos.
3 in | 1 ft | =0.25 ft |
12 in |
[pic 1]
10 in | 1 ft | =0.833 ft |
12 in |
6 in | 1 ft | =0.50 ft |
12 in |
[pic 2]
W=16 RAD/S |
= + [pic 3][pic 4][pic 5]
VB = VA + WAB x RB/A[pic 6][pic 7]
VB = 16 x ( 0.25 Cos 600 + 0.25 Sen 600 )[pic 11][pic 8][pic 9][pic 10]
0.25 | SEN 90 | = X = 0.288 |
SEN 60 |
VB = 2 + 3.464 (-)[pic 12][pic 13]
VB = 2 - 3.464 [pic 16][pic 14][pic 15]
= + [pic 17][pic 18][pic 19]
VD = VB + WBD x RD/B[pic 20]
VD/B = -WBD x ( 0.805 + 0.212 )[pic 24][pic 21][pic 22][pic 23]
VD/B = -0.805WBD + 0.212 WBD (-)[pic 25][pic 26]
VD/B = -0.805WBD + 0.212 WBD [pic 27][pic 28]
VD = 2 - 3.464 -0.805WBD + 0.212 WBD [pic 33][pic 29][pic 30][pic 31][pic 32]
- VD = - 3.464 + 0.212 WBD [pic 34][pic 35]
0 = 2 -0.805WBD [pic 36][pic 37]
WBD = 2. 484 rad/s VD = 2.937 ft/s
Aceleraciones
AB = Aa + AtB/A + AnB/A
Aa = 0
AtB/A = 0
AnB/A = - (wAB)2 * RB/A
AnB/A = - (16)2 * ( 0.25 Cos 600 + 0.25 Sen 600 )[pic 38][pic 39]
AnB/A = -32 -55.425[pic 40][pic 41]
AB = -32 -55.425[pic 42][pic 43]
AD = AB + AtD/B + AnD/B
AtD/B = αBD x RD/B
AtD/B = - αBD x ( 0.805 + 0.212 )[pic 44][pic 45][pic 46]
AtD/B = -0.805 αBD + 0.212 αBD [pic 47][pic 48]
AnD/B = - (wBD)2 * RD/B
AnD/B = - (2. 484)2 * ( 0.805 + 0.212 )[pic 49][pic 50]
AnD/B = -4.977 -1.308 [pic 51][pic 52]
AD = -32 -55.425 -0.805 αBD + 0.212 αBD -4.977 -1.308 [pic 53][pic 54][pic 55][pic 56][pic 57][pic 58]
AD = AD (cos 0 + sen 0 )[pic 59][pic 60]
AD = -32 -55.425 -0.805 αBD + 0.212 αBD -4.977 -1.308 [pic 61][pic 62][pic 63][pic 64][pic 65][pic 66][pic 67]
- AD = -32 + 0.212 αBD -4.977 [pic 68][pic 69][pic 70][pic 71]
0 = -55.425 -0.805 αBD -1.308 [pic 72][pic 73][pic 74][pic 75]
αBD = 70.475 rad/s2 AD = 16.42 ft/s2
15.125 SI LA MANIVELA AB GIRA ALREDEDOR DEL PUNTO A CON UNA VELOCIDAD ANGULAR CONSTANTE DE 900 RPM EN EL SENTIDO DE LAS MANECILLAS DEL RELOJ. DETERMINE LA ACELERACION DEL PISTON P CUANDO Ø=600.
W = 94.247 |
L = 0.15 m |
b = 0.05 m |
[pic 76]
= + [pic 77][pic 78][pic 79]
VB = VA + WAB x RB/A
VB = - 94.247 x ( 0.05 Cos 300 + 0.05 Sen 300 )[pic 80][pic 81][pic 82]
VB = - 4.08 - 2.33 (-)[pic 85][pic 83][pic 84]
VB = - 4.08 + 2.33 [pic 88][pic 89][pic 86][pic 87]
= + [pic 90][pic 91][pic 92]
...