TRABAJO DE PROBABILIDAD

Trabajo de probabilidad

3.

N=15 y P=25% (Binomial)

f(x;p,n)= (n¦x) p^x q^(n-x) □(⇒┬ ) f(x;0.25,15)= (15¦x) 〖0.25〗^x• 〖0.75〗^(15-x)

De 3 a 6

P(3≤x ≤6 )=1- ∑_(i=3)^6▒〖(15¦x) 〖0.25〗^x• 〖0.75〗^(15-x) 〗

P(3≤x ≤6 )=0.225+ 0.225+0.165+0.092=0.707

P(3≤x ≤6 )=70.7%

Menos de 4

P( x <4 )=1- ∑_(i=0)^4▒〖(15¦x) 〖0.25〗^x• 〖0.75〗^(15-x) 〗

P( x <4 )=0.013+0.067+0.156+0.225

P( x <4 )=0.461= 46.1%

De 3 a 6

P( x >6 )=1-P( x ≤6 ) = 1- ∑_(i=0)^5▒〖(15¦x) 〖0.25〗^x• 〖0.75〗^(15-x) 〗

P( x >6 )=1-[0.013+0.067+0.156+0.225+0.225+0.165+0.092]

P( x >6 )=1-0.942= 0.057=5.70%

6.

f(x;p)=( 1- 〖p )〗^(x-1) p (Geométrica)

P=0.04

P( x=4 )= ( 1- 〖0.04 )〗^(4-1)• 0.04=0.035=3.5%

P( x=4 )= ∑_(x=1)^2▒〖( 1- 〖0.04 )〗^(x-1)• 0.04=0.04+0.078=0.078=7.8%〗

8.

Distribución normal

μ_x=800 horas y σ_x^2=40 horas

Más de 829 horas

P(x >829)=P ( z > (x- μ_x )/( σ_x^2 )) □(⇒┬ ) P ( z > (829-800 )/( 40)) □(⇒┬ ) P ( z>0.725)

P(x >829)=1-[P ( z ≤0.73 )]=1-[ 0.76730 ]

P(x >829)=0.2327=23.27%

Máximo 820 horas

P(x ≤820)=P ( z ≤ (x- μ_x )/( σ_x^2 )) □(⇒┬ ) P ( z ≤ (820-800 )/( 40)) □(⇒┬ ) P ( z≤0.5)

P(x ≤820)=0.69146

P(x ≤820)=69.146%

Entre 778 y 834 horas

P( 778 ≤x ≤834)=P ((778- μ_x )/( σ_x^2 ) z ≤ (834- μ_x )/( σ_x^2 )) □

P( 778 ≤x ≤834)= P (-0.55 ≤ z ≤0.85 )

P( 778 ≤x ≤834)=0.80234-[ 1-0.70884 ]

P( 778 ≤x ≤834)=0.51118=51.118%

5.

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