Actividad Geometria analitica

ACTIVIDAD 4 GEOMETRIA ANALITICA

A(0,0) ; B(10,0) ; C(13,0) ; D(16,-4) ; E(20,-4) ; F(24,0) ; G(26,0) ; H(27,0) ; I(37,0) ; J(20,30) ; K(19,30) ; L(16,30)

PUNTO SECCION PERIMETRO(m) AREA (m2) Volumen (m3) Costo (USD)

A,B,L (1)

Enrocamiento AB+BL+LA

10+30.59+34

SUBTOTAL=74.59 150 150(50)

SUBTOTAL=

7500 500(750)

SUBTOTAL=

3,750,000

B,C,D,E,F,G,K,L (2)

CORAZON

IMPERMEBALE

MATERIAL FINO

BC+CD+DE+EF+FG+GK+KL+LB

3+5+4+5.66+2+30.80+3+30.59

SUBTOTAL= 84.05 315 315(50)

SUBTOTAL=

15,750 200(15,750)

SUBTOTAL=

3,150,000

G,H,J,K (3)

FILTRO DE TRANSICION DE GRAVA Y ARENA GH+HJ+JK+KG

1+30.80+1+30.80

SUBTOTAL=63.60 30 30(50)

SUBTOTAL=

1,500 300(1500)

SUBTOTAL=

450,000

H,I,J (4)

ENROCAMIENTO HI+IJ+JH

10+34.48+30.80

SUBTOTAL= 75.28 150 150(50)

SUBTOTAL=

7,500 400(7500)

SUBTOTAL = 3,000,000

TOTAL PERIMETRO=

29752 TOTAL

AREA=

645 TOTAL VOLUMEN

32,250 COSTO TOTAL= 10,350,000 USD

LINEA Nº X2 X1 Y2 Y1

1 16 0 30 0 =34---------LA

2 16 10 30 0 =30.59-------LB

3 16 13 -4 0 =5---------CD

4 24 20 0 -4 =5.66--------EF

5 19 26 30 0 =30.80-------GK

6 20 27 30 0 =30.80--------HJ

7 20 37 30 0 34.48-------IJ

AB = √(X2) –(X1)²+ (Y2)-Y1)²

1.- AB= √ (16-0)² +(30-0)² =√ (16)² +(30)² =√(256)+(900) = √1156= 34

2.-AB= √(16-10)²+(30)-0)²=√(16)+(30)²=√36+900=√936=30.59

3.- AB= √(16-13)²+(-4-0)²=√(13)²+(-4)²=√9+16=√25=5

4.- AB =√AB(24-20)²+(0(-4)²=√ 16+16)=√32=5.66

5.- AB=√(19-26)²+(30-0)²=√(-7)²+(30)²=√49+900=√949=30.80

6.-AB=√(20-27)²+(30-0)²=√(-7)²+(30)²=√49+900=√949=30.80

7.- AB=√(20-37)²+(30-0)²=√(17)²+(30)²=√289+900=√1189=34.48

AREA FIGURA 2 CORAZON IMPERMEABLE

B=10,0 10 0

C=13,0 13 0

D=16,-4 16 -4

E=20,-4 20 -4

F=24,0 24 0

G=26,0 26 0

K=19,30 19 30

L=16,30 16 30

10 0 AREA FIGURA 1 ENROCAMIENTO

A=0,0 0 0

B=10,0 10 0

L=16,30 16 30

0 0

A=[(0)(0)+(10)(30)+(16)(0)]-[(0)(30)+(16)(0)+(10)(10)]/2

A=(10)(30)/2

A=300/2 A=50U²

A=[(10)(0)+(13)(-4)+(16)(-4)+(20)(0)+(24)(0)+(26)(30)+(19)(30)+(16)(0)]-[(10)(30)+(16)(30)+(19)(0)+(26)(0)+(24)(-4)+(20)(-4)+(16)(0)+(13)(0)]

A=[(0)+(-52)+(-64)+(0)+(0)+(780)+(570)+(0)]=1234

[(300)+(480)+(0)+(-80)+(0)+(0)]=604

A=[1234]-[604]/2

A=630/2

A=315 U²

VOLUMEN (m³)

315(50)=15750 SUBTOTAL

COSTO USD 500(15750)=7875000 USD

FIGURA 3 FILTRO DE TRANSICION

G=26,0 26 0

H=27,0 27 0

J=20,30 20 30

K=19,30 19 30

26 0

A=[(26)(0)+(27)(30)+(20)(30)+(19)(0)]-[(26)(30)+(19)(30)+(20)(0)+(20)(0)

A=[(0)+(810)+(600)+(0)]-[(780)+(570)+(0)+(0)]

A=[1410]-[1350]/2

A=60/2

A=30U²

VOLUMEN (m³) 30(50)=1500

500(1500)=750.00

COSTO USD

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