Solucionario
Enviado por saristizabals • 19 de Abril de 2014 • 2.947 Palabras (12 Páginas) • 231 Visitas
Chapter 4
Nominal and Effective Interest Rates
Solutions to Problems
4.1 (a) monthly (b) quarterly (c) semiannually
4.2 (a) quarterly (b) monthly (c) weekly
4.3 (a) 12 (b) 4 (c) 2
4.4 (a) 1 (b) 4 (c) 12
4.5 (a) r/semi = 0.5*2 = 1% (b) 2% (c) 4%
4.6 (a) i = 0.12/6 = 2% per two months; r/4 months = 0.02*2 = 4%
(b) r/6 months = 0.02*3 = 6%
(c) r/2 yrs = 0.02*12 = 24%
4.7 (a) 5% (b) 20%
4.8 (a) effective (b) effective (c) nominal (d) effective (e) nominal
4.9 i/6months = 0.14/2 = 7%
4.10 i = (1 + 0.04)4 – 1
= 16.99%
4.11 0.16 = (1 + r/2)2 –1
r = 15.41%
4.12 Interest rate is stated as effective. Therefore, i = 18%
4.13 0.1881 = (1 + 0.18/m)m – 1
Solve for m by trial and gives m = 2
4.14 i = (1 + 0.01)2 –1
i = 2.01%
4.15 i = 0.12/12 = 1% per month
Nominal per 6 months = 0.01(6) = 6%
Effective per 6 months = (1 + 0.06/6)6 – 1
= 6.15%
4.16 (a) i/week = 0.068/26 = 0.262%
(b) effective
4.17 PP = weekly; CP = quarterly
4.18 PP = daily; CP = quarterly
4.19 From 2% table at n =12, F/P = 1.2682
4.20 Interest rate is effective
From 6% table at n = 5, P/G = 7.9345
4.21 P = 85(P/F,2%,12) = 85(0.7885)
= $67.02 million
4.22 F = 2.7(F/P,3%,60)
= 2.7(5.8916)
= $15.91 billion
4.23 P = 5000(P/F,4%,16)
= 5000(0.5339)
= $2669.50
4.24 P = 1.2(P/F,5%,1) (in $million)
= 1.2(0.9524)
= $1,142,880
4.25 P = 1.3(P/A,1%,28)(P/F,1%,2) (in $million)
= 1.3(24.3164)(0.9803)
= $30,988,577
4.26 F = 3.9(F/P,0.5%,120) (in $billion)
= 3.9(1.8194)
= $7,095,660,000
4.27 P = 3000(250 – 150)(P/A,4%,8) (in $million)
= 3000(100)(6.7327)
= $2,019,810
4.28 F = 50(20,000,000)(F/P,1.5%,9)
= 1,000,000,000(1.1434)
= $1.1434 billion
4.29 A = 3.5(A/P,5%,12) (in $million)
= 3.5(0.11283)
= $394,905
4.30 F = 10,000(F/P,4%,4) + 25,000(F/P,4%,2) + 30,000(F/P,4%,1)
= 10,000(1.1699) + 25,000(1.0816) + 30,000(1.04)
= $69,939
4.31 i/wk = 0.25%
P = 2.99(P/A,0.25%,40)
= 2.99(38.0199)
= $113.68
4.32 i/6 mths = (1 + 0.03)2 – 1
A = 20,000(A/P,6.09%,4)
= 20,000 {[0.0609(1 + 0.0609)4]/[(1 + 0.0609)4-1]}
= 20,000(0.28919)
= $5784
4.33 F = 100,000(F/A,0.25%,8)(F/P,0.25%,3)
= 100,000(8.0704)(1.0075)
= $813,093
Subsidy = 813,093 – 800,000 = $13,093
4.34 P = (14.99 – 6.99)(P/A,1%,24)
= 8(21.2434)
= $169.95
4.35 First find P, then convert to A
P = 150,000{1 – [(1+0.20)10/(1+0.07)10}]}/(0.07 – 0.20)
= 150,000(16.5197)
= $2,477,955
A = 2,477,955(A/P,7%,10)
= 2,477,955(0.14238)
= $352,811
4.36 P = 80(P/A,3%,12) + 2(P/G,3%,12)
P = 80(9.9540) + 2(51.2482)
= $898.82
4.37 2,000,000 = A(P/A,3%,8) + 50,000(P/G,3%,8)
2,000,000 = A(7.0197) + 50,000(23.4806)
A = $117,665
4.38 P = 1000 + 2000(P/A,1.5%,12) + 3000(P/A,1.5%,16)(P/F,1.5%,12)
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