Practica Calculo
Enviado por melissa_31 • 1 de Mayo de 2013 • 8.681 Palabras (35 Páginas) • 321 Visitas
FORMULA 1
Y=13
dy = d(13)
dx dx
dy = 0
dx
Y= 6c2
dy = d(6c2)
dx dx
dy = 0
dx
Y= 9x
dy = d(9x)
dx dx
dy = 0
dx
Y= c
dy = d(c)
dx dx
dy = 0
dx
Y= 3
dy = d(3)
dx dx
dy = 0
dx
FORMULA 2
Y= x
dy = d(x)
dx dx
dy = 1
dx
Y= 6x
dy = d(6x)
dx dx
dy = 6dx
dx dx
dy = 6(1)
dx
dy = 6
dx
Y= Bx+x
dy = d(Bx+x)
dx dx
dy = Bdx + dx
dx dx dx
dy = B (1) +1
dx
dy = B+1
dx
Y= x+x
dy = d(x+x)
dx dx
dy = dx + dx
dx dx dx
dy = 1+1
dx
dy = 2
dx
Y= 8x
dy = d(8x)
dx dx
dy = 8dx
dx dx
dy = 8(1)
dx
dy = 8
d
FORMULA 3
Y= 2a+ab+7b
dy = d( 2a+ab+7b)
dx dx
dy = d(2a)+ d(ab) + d(7b)
dx dx dx dx
dy = 0+0+0
dx
dy = 0
dx
Y=c+x+9
dy=d(c+x+9)
dx dx
dy=d(c)+dx+d(9)
dx dx dx dx
dy=0+1+0
dx
dy=1
dx
Y= 10b+bc+a2
dy = d(10b+bc+a2)
dx dx
d
y = d(10b)+ d(bc) + d(a2)
dx dx dx dx
dy = 0+0+0
dx
dy = 0
d
Y= 8x+10x+x+b
dy = d(6x+3x+x+b)
dx dx
dy = d(6x)+ d(3x) + d(x) + d(b)
dx dx dx dx dx
dy = 6dx+ 3dx + dx + db
dx dx dx dx dx
dy = 6(1)+3(1)+1+0
dx
dy = 6+3+1+0
dx
dy = 10
dx
Y=x+x+x
dy=d(x+x+x)
dx dx
dy= dx + dx+dx
dx dx dx dx
dy=1+1+1
dx
dy= 3
dx
FORMULA 4
Y= 4x
dy = d(4x)
dx dx
dy = 4dx
dx dx
dy = 4(1)
dx
dy = 4
dx
Y= 21x
dy = d(21x)
dx dx
dy = 21dx
dx
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