La presa. Tabla resumen
Enviado por AYERIM78 • 9 de Agosto de 2014 • Trabajos • 856 Palabras (4 Páginas) • 399 Visitas
LA PRESA
Tabla resumen
Número Sección Perímetro (m) Área (m2)
1 Enrocamiento 1 93.52 200
2 Corazón 105.27 417.50
3 Filtro 83.20 40
4 Enrocamiento 2 92.68 180
Primero de damos una variable a cada coordenada:
A= (36, 0) G= (13, 0)
B= (27, 0) H= (10, 0)
C= (26. 0) I= (0, 0)
D= (24, 0) J= (16, 40)
E= (20, -5) k= (19, 40)
F= (16, -5) L= (20, 40)
AB = √[(xa – xb)2 + (ya – yb)2] = √(36 -27)2 + (0 – 0)2 =
√(9)2 + (0)2 = 81
√81 = 9
BC = √[(xb – xc)2 + (yb – yc)2] = √(27 -26)2 + (0 – 0)2 =
√(1)2 + (0)2 = 1
√1 = 1
CD = √[(xc – xd)2 + (yc – yd)2] = √(26 -24)2 + (0 – 0)2 =
√(2)2 + (0)2 = 4
√4 = 2
DE = √[(xd – xe)2 + (yd – ye)2] = √(24 -20)2 + (0 – 5)2 =
√(4)2 + (-5)2 = √16 + 25 = 41
√41 = 6.40
EF = √[(xe – xf)2 + (ye – yf)2] = √(20 - 16)2 + (-5 + 5)2 =
√(4)2 + (0)2 = 16
√16 = 4
FG = √[(xf – xg)2 + (yf – yg)2] = √(16 -13)2 + (-5 – 0)2 =
√(3)2 + (5)2 = √9 + 25 = 34
√34 = 5.83
GH = √[(xg – xh)2 + (yg – yh)2] = √(13 -10)2 + (0 – 0)2 =
√(3)2 + (0)2 = 9
√9 = 3
HI = √[(xh – xi)2 + (yh – yi)2] = √(10 -0)2 + (0 – 0)2 =
√(10)2 + (0)2 = 100
√100 = 10
IJ = √[(xi – xj)2 + (yi – yj)2] = √(0 -16)2 + (0 – 40)2 =
√(-16)2 + (-40)2 = √256 + 1600 = 1856
√1856 = 43.08
JK = √[(xj – xk)2 + (yj – yk)2] = √(16 -19)2 + (40 – 40)2 =
√(-3)2 + (-0)2 = 9
√9 = 3
KL = √[(xk – xl)2 + (yk – yl)2] = √(19 -20)2 + (40 – 40)2 =
√(-1)2 + (0)2 = 1
√1 = 1
LA = √[(xl – xa)2 + (yl – ya)2] = √(20 -36)2 + (40 – 0)2 =
√(-16)2 + (40)2 = √256 + 1600 = 1856
√1856 = 43.08
JH = √[(xj – xh)2 + (yj – yh)2] = √(16 -10)2 + (40 – 0)2 =
√(6)2 + (40)2 = √36 + 1600 = 1636
√1636 = 40.44
KC = √[(xK – xC)2 + (yK – yC)2] = √(19 -26)2 + (40 – 0)2 =
√(-7)2 + (40)2 = √49 + 1600 = 1649
√1649 = 40.60
LB = √[(xl – xb)2 + (yl – yb)2] = √(20 -27)2 + (40 – 0)2 =
√(-7)2
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